Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A tertiary bromide is dissolved in aqueous ethanol. It reacts by the mechanism and follows first-order kinetics. Its rate constant is at the temperature of the experiment (a value chosen for this problem). Take . Find the half-life, the time for of the bromide to react, and the percentage of the bromide left after . The first-order law gives the fraction left as .
is first order, , with half-life . A planar carbocation gives a racemic or partly racemic product. The enantiomeric excess is the difference of the two shares, and the observed rotation is the specific rotation times tube length times concentration times the excess. A carbocation can rearrange to a more stable one by a hydride shift.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. Half-life. .
Step 2. 87.5 percent. Then is left, which is . So three half-lives pass: .
Step 3. Left after 600 s. . The fraction left is , which is .
Answer: , and .
Check. is just a little longer than , so a little less than is left.
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