A tank holds 100.0 kg of oleum that is 20.0 % free sulphur trioxide by mass, with 80.0 % sulphuric…
Contributed by StemPy LabTry it on paper first. A hint, the key idea and the worked solution are here when you need them.
A tank holds of oleum that is free sulphur trioxide by mass, with sulphuric acid. Water is added to turn all the free sulphur trioxide into sulphuric acid. Take the molar masses as SO3 , H2SO4 and H2O . Find three things. First, the mass of water that is needed. Second, the total mass of pure sulphuric acid that results. Third, the mass of acid that can be made from it by adding more water.
Need a reminder? The key ideaShow
The worked solution
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. Free sulphur trioxide. is .
Step 2. Water. needs one H2O for each SO3: .
Step 3. New acid. . The total is of pure acid.
Step 4. The 98 percent acid. .
Answer: of water, of acid and of acid.
Check. Mass is kept: . The extra water in the 98 percent acid is .
Discussion (0)
Log in to join the discussion.
Loading…