Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A student studies the cubic , where is a real number. She wants to be strictly increasing on the whole real line, with no interval where the graph falls.
Find . Write the condition on that keeps from ever being negative. Then give the largest and the smallest value of that work. At each of these two extreme values, becomes the square of a bracket times a number. Say why is still strictly increasing there, even though is at one point.
Check your answer in two ways. Take , which lies in your range, and show that is positive for every . Take , which lies outside it, and find a value of at which is negative.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. The derivative. .
Step 2. The condition. The parabola opens upwards, so for all exactly when its discriminant is not positive: , which is .
Step 3. The values of . , so .
Step 4. The extreme values. For , . For , . Each is at one point only.
Step 5. Why it still works. A derivative that is and is only at an isolated point leaves strictly increasing. The graph flattens for an instant at (or ) and then continues to rise.
Check. For , . For , , and , so falls near .
Answer: the largest value is and the smallest is .
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If on an interval, is strictly increasing there. If , it is strictly decreasing. Solve , test the sign of in each gap, and write the intervals. Isolated zeros of do not stop from being strictly monotonic.