Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A student has strips of zinc, copper and silver, and solutions of their nitrates. Say whether there is a reaction, and write the net ionic equation if there is: (a) copper in silver nitrate; (b) silver in copper(II) nitrate; (c) zinc in copper(II) nitrate; (d) copper in zinc nitrate. Then put zinc, copper and silver in order as reducing agents.
Oxidation is loss of electrons and reduction is gain. The reducing agent gives electrons and is oxidised. The oxidising agent takes electrons and is reduced. Electrons lost equal electrons gained. A stronger reducing agent wins the competition for electrons.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. (a). Copper is a stronger reducing agent than silver, so it reacts: .
Step 2. (b). Silver is the weaker one, so there is no reaction.
Step 3. (c). Zinc beats copper: .
Step 4. (d). Copper is weaker than zinc, so there is no reaction.
Step 5. The order. The two reactions that work show zinc beats copper and copper beats silver.
Answer: (a) and (c) react; (b) and (d) do not. As reducing agents, zinc is strongest, then copper, then silver.
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