A solution of 0.150 mol/L has a conductivity of 0.0165 S/cm…

The molar conductivity is $\Lambda_m = \dfrac{\kappa}{c}$. With $\kappa$ in $\text{S/m}$ and $c$ in $\text{mol/L}$, $\Lambda_m = \dfrac{10\,\kappa}{c}$ in $\text{S cm}^2/\text{mol}$. With $\kappa$ in $\text{S/cm}$, $\Lambda_m = \dfrac{1000\,\kappa}{c}$. A strong electrolyte follows $\Lambda_m = \Lambda_m^\circ - A\sqrt{c}$. For a weak electrolyte, $\alpha = \dfrac{\Lambda_m}{\Lambda_m^\circ}$.