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A solution has a concentration of 0.0650 mol/L…

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A solution has a concentration of $0.0650\ \text{mol/L}$ . It is placed in a cell with a cell constant of $130\ \text{m}^{-1}$ , and the cell reads $250\ \Omega$ . Find the conductivity, and the molar conductivity in $\text{S cm}^2/\text{mol}$ and in $\text{S m}^2/\text{mol}$ .

Need a reminder? The key ideaShow

The molar conductivity is $\Lambda_m = \dfrac{\kappa}{c}$ . With $\kappa$ in $\text{S/m}$ and $c$ in $\text{mol/L}$ , $\Lambda_m = \dfrac{10\,\kappa}{c}$ in $\text{S cm}^2/\text{mol}$ . With $\kappa$ in $\text{S/cm}$ , $\Lambda_m = \dfrac{1000\,\kappa}{c}$ . A strong electrolyte follows $\Lambda_m = \Lambda_m^\circ - A\sqrt{c}$ . For a weak electrolyte, $\alpha = \dfrac{\Lambda_m}{\Lambda_m^\circ}$ .

The worked solution

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A solution has a concentration of 0.0650 mol/L…

The worked solution

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