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A solution has 6.84 g of sucrose, of molar mass 342 g/mol, in 250 mL of solution at 310 K…

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A solution has $6.84\ \text{g}$ of sucrose, of molar mass $342\ \text{g/mol}$ , in $250\ \text{mL}$ of solution at $310\ \text{K}$ . Find its osmotic pressure in atm, and in kPa.

Need a reminder? The key ideaShow

The osmotic pressure of a dilute solution is $\pi = CRT$ , with $C$ in mol/L and $T$ in kelvin. $R = 0.0821\ \text{L atm K}^{-1}\text{mol}^{-1}$ gives atm, and $R = 8.314\ \text{J K}^{-1}\text{mol}^{-1}$ gives kPa. Isotonic solutions have equal $\pi$ . A column of height $h$ of a liquid of density $\rho$ gives a pressure $\rho g h$ .

The worked solution

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