A sledge starts from rest and slides 7.2 m down an icy slope at 22°…

Step 1. Acceleration. $a = 9.8\ \text{m/s}^2 \sin 22^\circ = 3.67\ \text{m/s}^2$.

Step 2. Time. $t = \sqrt{\dfrac{2s}{a}} = \sqrt{\dfrac{14.4\ \text{m}}{3.67\ \text{m/s}^2}} = 1.98\ \text{s}$.

Step 3. Speed. $v = at = 3.67\ \text{m/s}^2 \times 1.98\ \text{s} = 7.27\ \text{m/s}$.