Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A radio mast stands at , with coordinates in metres. A straight cable passes through with direction ratios . A technician must attach a sensor to the cable at points that are exactly metres from the mast. She first finds the shortest distance from the mast to the cable and the foot of the perpendicular. She then uses Pythagoras along the cable to locate the two points. Find the distance of the mast from the cable, the -coordinate of the foot, and the -coordinates of the two points, giving the larger -coordinate first. A third technician wonders whether the answer would change if the cable were described by the direction ratios instead. It would not, because both give the same line.
The foot of the perpendicular from to the line has . The distance is , or .
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. The foot. and . So and .
Step 2. The distance. , and metres.
Step 3. Pythagoras along the cable. The sensor is metres from , and is perpendicular to the cable. So metres.
Step 4. The parameter step. , so metres is steps of . The points are and .
Check. metres.
Answer: metres, the foot has , and the two points have and .
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