Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A plant feeds of nitrogen and of hydrogen into a reactor. Take the molar masses as N2 , H2 and NH3 . Suppose that the reaction goes to completion. Find the mass of ammonia that forms, and the mass of the reagent that is left over. In real life only of the nitrogen is converted in one pass through the reactor. Find the mass of ammonia made in one pass.
Nitrogen has only the second shell, so its covalency is at most 4. Phosphorus can hold more than eight electrons. The oxidation state is found by taking oxygen as , hydrogen as and making the sum equal to the charge. In the Haber process, 3 mol of H2 are used for each mole of N2, and 2 mol of NH3 form. The reagent that runs out first limits the product. Percent yield is .
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Given. of N2 and of H2.
Step 1. Moles. and .
Step 2. The limiting reagent. 1000 mol of N2 needs 3000 mol of H2. There are 5000 mol, so nitrogen is limiting and hydrogen is in excess.
Step 3. Ammonia. . The mass is .
Step 4. Hydrogen left. , which is .
Step 5. One pass. .
Answer: of ammonia, of hydrogen left, and in one pass.
Check. The masses balance: in, and out.
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