A plant burns 8.50 t of ammonia each day in the Ostwald process…
Contributed by StemPy LabTry it on paper first. A hint, the key idea and the worked solution are here when you need them.
A plant burns of ammonia each day in the Ostwald process. The overall yield, from ammonia to nitric acid, is . Take the molar masses as NH3 and HNO3 . The acid is sold as a solution by mass. Find the mass of pure nitric acid, the mass of solution, and the mass of ammonia that is not turned into acid.
Need a reminder? The key ideaShow
Oxidation states of nitrogen run from to . Nitric acid is reduced to NO2 when concentrated and to NO, N2O or NH4+ when dilute. Count electrons: a metal atom that gives up electrons needs electrons to be taken by the nitrogen. At 273 K and 1 atm, 1 mol of gas fills 22.4 L. The Ostwald process gives 1 mol of HNO3 for each mole of NH3 at a full yield.
The worked solution
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Given. of ammonia, a yield of .
Step 1. Moles. of ammonia.
Step 2. Acid at a full yield. One mole of ammonia gives one mole of nitric acid, so .
Step 3. At 94 percent. of pure acid.
Step 4. The solution. .
Step 5. Ammonia lost. of ammonia is not turned into acid.
Answer: of pure acid, of solution and of ammonia lost.
Check. The mass ratio gives at a full yield.
Discussion (0)
Log in to join the discussion.
Loading…