A glass tube of inner radius 0.50 mm is dipped into water and then into mercury…

Step 1. Water. $h = \dfrac{2 \times 0.0728 \times \cos 0^\circ}{998 \times 9.81 \times 0.50 \times 10^{-3}} = \dfrac{0.1456}{4.895} = 0.0297\ \text{m} = 29.7\ \text{mm}$.

Step 2. Mercury. $h = \dfrac{2 \times 0.486 \times \cos 140^\circ}{13\,534 \times 9.81 \times 0.50 \times 10^{-3}} = \dfrac{-0.7446}{66.39} = -0.0112\ \text{m}$. The mercury falls by $11.2\ \text{mm}$.