A gas with γ = 1.40 at 5.5 × 10⁵ Pa fills 1.2 litres.

Step 1. Pressure. $p_2 = 5.5 \times 10^{5}\ \text{Pa} \times 0.25^{1.40} = 7.90 \times 10^{4}\ \text{Pa}$.

Step 2. The two products. $p_1V_1 = 660\ \text{J}$ and $p_2V_2 = 7.90 \times 10^{4}\ \text{Pa} \times 4.8 \times 10^{-3}\ \text{m}^3 = 379\ \text{J}$.

Step 3. Work. $W = \dfrac{660\ \text{J} - 379\ \text{J}}{0.40} = 702\ \text{J}$.