A dipole is made of +2.4 nC and -2.4 nC, 3.0 mm apart…

Step 1. The moment. $p = q \times 2a = 2.4 \times 10^{-9}\ \text{C} \times 3.0 \times 10^{-3}\ \text{m} = 7.2 \times 10^{-12}\ \text{C m}$. It points from the negative charge to the positive charge.

Step 2. On the axis. $E = \dfrac{2kp}{r^3} = \dfrac{2 \times 9.0 \times 10^{9}\ \text{N m}^2/\text{C}^2 \times 7.2 \times 10^{-12}\ \text{C m}}{(0.20\ \text{m})^3} = \dfrac{0.1296}{0.0080}\ \text{N/C} = 16.2\ \text{N/C}$, along $\vec{p}$.

Step 3. On the equatorial line. $E = \dfrac{kp}{r^3} = 8.10\ \text{N/C}$, against $\vec{p}$.