A cell with a cell constant of 84.0 m⁻¹ is filled with a solution of a strong electrolyte and reads…

Step 1. Before. $\kappa_1 = \dfrac{84.0\ \text{m}^{-1}}{120\ \Omega} = 0.700\ \text{S/m}$.

Step 2. After. $\kappa_2 = \dfrac{84.0\ \text{m}^{-1}}{230\ \Omega} = 0.365\ \text{S/m}$.

Step 3. The concentrations. After the dilution, $c_2 = \dfrac{c_1}{2}$.

Step 4. The molar conductivities. $\dfrac{\Lambda_2}{\Lambda_1} = \dfrac{\kappa_2/c_2}{\kappa_1/c_1} = \dfrac{\kappa_2}{\kappa_1} \times \dfrac{c_1}{c_2} = \dfrac{0.365}{0.700} \times 2 = 1.04$.