EasyChemistryHigh School (11–12)Redox Reactions › Oxidation Number and Types of Redox ReactionsConceptualA-LevelAPIB
A cell is written as Ni(s) mid Ni²⁺(aq) ∥ Ag⁺(aq) mid Ag(s)…
Contributed by StemPy LabTry it on paper first. A hint, the key idea and the worked solution are here when you need them.
A cell is written as . Say which electrode is the anode and which is the cathode. Write the half-reaction at each electrode, say which way the electrons flow in the wire, and say which rod gets thicker.
Need a reminder? The key ideaShow
A half-cell is a metal in a solution of its ions. In a cell that makes electricity, the anode is where oxidation happens and is negative, and the cathode is where reduction happens and is positive. Electrons go from anode to cathode in the wire. and one mole of electrons carries .
The worked solution
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Given. The anode is on the left and the cathode on the right.
Step 1. The electrodes. Nickel is the anode and silver is the cathode.
Step 2. The half-reactions. At the anode, . At the cathode, .
Step 3. The electrons. They go from the anode to the cathode, so from nickel to silver in the wire.
Step 4. The thick rod. Silver atoms deposit on the cathode, so the silver rod gets thicker. The nickel rod gets thinner.
Answer: nickel is the anode (negative) and silver is the cathode (positive). Electrons flow from nickel to silver, and the silver rod thickens.
Discussion (0)
Log in to join the discussion.
Loading…