A 2.5 kg block is thrown along a floor at 7.0 m/s…

Try it on paper first. A hint, the key idea and the worked solution are here when you need them.

A $2.5\ \text{kg}$ block is thrown along a floor at $7.0\ \text{m/s}$ . The coefficient of kinetic friction is $0.35$ . Taking $g = 9.8\ \text{m/s}^2$ , find how far it slides and how much heat is produced.

Need a reminder? The key ideaShow

With friction, total energy is still conserved: $K_1 + U_1 = K_2 + U_2 + E_{\text{heat}}$ , and the heat is the work against friction, $f \times$ the path length.

The worked solution

Have you tried it?

Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.

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