A 9.0 Ω resistor X is in the left gap of a meter bridge and a 6.0 Ω box is in the right gap…
Contributed by StemPy LabTry it on paper first. A hint, the key idea and the worked solution are here when you need them.
A resistor is in the left gap of a meter bridge and a box is in the right gap. Where does the bridge balance? A resistor is then joined in parallel with the box. Where does it balance now?
Need a reminder? The key ideaShow
At balance, , with measured from the end where is joined. A resistor in parallel with makes the right arm . For a wire, .
The worked solution
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. Before. .
Step 2. The new right arm. .
Step 3. After. .
Check. A smaller right arm means the jockey must move further from the left end. It went from to .
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