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  1. Problems
  2. /2-Methylpropan-1-ol has the condensed formula CH₃CH(CH₃)CH₂OH…
MediumChemistryHigh School (11–12)Organic Chemistry: Some Basic Principles and Techniques › Classification, IUPAC Nomenclature and IsomerismNumericalA-LevelIB

2-Methylpropan-1-ol has the condensed formula CH₃CH(CH₃)CH₂OH…

StemPy LabContributed by StemPy Lab

Try it on paper first. A hint, the key idea and the worked solution are here when you need them.

2-Methylpropan-1-ol has the condensed formula CH3CH(CH3)CH2OH\text{CH}_{3}\text{CH(CH}_{3}\text{)CH}_{2}\text{OH}CH3​CH(CH3​)CH2​OH. Find how many carbon atoms and how many hydrogen atoms it has, which gives its molecular formula. Then find its total number of sigma bonds.

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Carbon forms four bonds. Four atoms around it: sp3sp^3sp3, tetrahedral, 109.5 degrees. Three atoms around it: sp2sp^2sp2, planar, 120 degrees. Two atoms around it: spspsp, linear, 180 degrees. Every bond holds one sigma bond. A double bond adds one pi bond, and a triple bond adds two. In a bond-line drawing, every corner and every end is a carbon atom, and each carbon has four bonds in all.

The worked solution

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Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.

Step 1. Carbon. The groups are CH3\text{CH}_{3}CH3​, CH\text{CH}CH, CH3\text{CH}_{3}CH3​ and CH2\text{CH}_{2}CH2​. That makes 4 carbon atoms.

Step 2. Hydrogen. 3 + 1 + 3 + 2 = 9 on carbon, plus 1 on oxygen. Total: 10. The molecular formula is C4H10O\text{C}_{4}\text{H}_{10}\text{O}C4​H10​O.

Step 3. Bonds. There are 15 atoms (4 + 10 + 1). A molecule with no ring has one bond fewer than it has atoms, so there are 14 bonds. All are single, so all are sigma.

Answer: C4H10O\text{C}_{4}\text{H}_{10}\text{O}C4​H10​O, with 10 hydrogen atoms and 14 sigma bonds.

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  1. Carbon, shapes and structural formulaeClassification, Nomenclature and Isomerism

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