2-Methylbutane, CH₃CH(CH₃)CH₂CH₃, gives four monohalo products…

2-Methylbutane, $\text{CH}_3\text{CH(CH}_3\text{)CH}_2\text{CH}_3$, gives four monohalo products. Replacing a hydrogen on carbon 1 or on the methyl branch gives 1-halo-2-methylbutane (6 hydrogen atoms in all). Carbon 2 gives 2-halo-2-methylbutane (1 hydrogen atom). Carbon 3 gives 2-halo-3-methylbutane (2 hydrogen atoms). Carbon 4 gives 1-halo-3-methylbutane (3 hydrogen atoms). At room temperature with chlorine, the reactivities of one primary, secondary and tertiary hydrogen are $1.0 : 3.8 : 5.0$. With bromine at $125\ ^\circ\text{C}$ they are $1 : 82 : 1640$. Find the percentage of each chloro product, and the percentage of 2-bromo-2-methylbutane in the bromination.