A brief note on Travelling Waves and Wave Speed . Read it before a test. Try each question at the end before you open its answer.
Kinds of wave A wave carries energy and a pattern. Each particle of the medium only moves about its own place. Transverse: the particles move across the direction of travel. Crests and troughs. Longitudinal: the particles move along the direction of travel. Compressions and rarefactions. Mechanical waves need a medium. Gases and liquids carry only longitudinal waves in their bulk. The equation of a wave Towards + x +x + x : y = a sin ( k x − ω t + ϕ ) y = a\sin(kx - \omega t + \phi) y = a sin ( k x − ω t + ϕ ) . Towards − x -x − x : k x + ω t kx + \omega t k x + ω t . k = 2 π λ k = \dfrac{2\pi}{\lambda} k = λ 2 π , in rad/m. ω = 2 π T = 2 π f \omega = \dfrac{2\pi}{T} = 2\pi f ω = T 2 π = 2 π f , in rad/s. Wave speed: v = ω k = f λ v = \dfrac{\omega}{k} = f\lambda v = k ω = f λ . Particle velocity: u = − a ω cos ( k x − ω t + ϕ ) u = -a\omega\cos(kx - \omega t + \phi) u = − aω cos ( k x − ω t + ϕ ) , at most a ω a\omega aω . Phase difference between two points: Δ ϕ = k Δ x \Delta\phi = k\Delta x Δ ϕ = k Δ x . What sets the speed String: v = T μ v = \sqrt{\dfrac{T}{\mu}} v = μ T , with μ \mu μ in kg/m. Fluid: v = B ρ v = \sqrt{\dfrac{B}{\rho}} v = ρ B . Solid rod: v = Y ρ v = \sqrt{\dfrac{Y}{\rho}} v = ρ Y . Gas: v = γ p ρ = γ R T M v = \sqrt{\dfrac{\gamma p}{\rho}} = \sqrt{\dfrac{\gamma R T}{M}} v = ρ γ p = M γ R T (Laplace). Newton's p / ρ \sqrt{p/\rho} p / ρ is too low. v ∝ T v \propto \sqrt{T} v ∝ T , in kelvin. Pressure alone does not change it. Damp air carries sound a little faster. A worked example A wave is y = 0.02 sin ( 4 x − 48 t ) y = 0.02\sin(4x - 48t) y = 0.02 sin ( 4 x − 48 t ) , in SI units, on a rope with μ = 0.25 kg/m \mu = 0.25\ \text{kg/m} μ = 0.25 kg/m . Find its wavelength, speed and the tension in the rope.
Wavelength. λ = 2 π 4 rad/m = 1.57 m \lambda = \dfrac{2\pi}{4\ \text{rad/m}} = 1.57\ \text{m} λ = 4 rad/m 2 π = 1.57 m . Speed. v = 48 rad/s 4 rad/m = 12 m/s v = \dfrac{48\ \text{rad/s}}{4\ \text{rad/m}} = 12\ \text{m/s} v = 4 rad/m 48 rad/s = 12 m/s . Tension. v 2 = T / μ v^2 = T/\mu v 2 = T / μ , and we want T T T , so T = μ v 2 = 0.25 kg/m × ( 12 m/s ) 2 = 36 N T = \mu v^2 = 0.25\ \text{kg/m} \times (12\ \text{m/s})^2 = 36\ \text{N} T = μ v 2 = 0.25 kg/m × ( 12 m/s ) 2 = 36 N . Practice with new numbers
A program to try The program works through the example above.
Run it. Compare the numbers with the worked example.
1. Change mu = 0.25 to mu = 1.0. By how many times does the tension grow?
Mistakes to avoid Wave speed and particle speed. They are different. One is ω / k \omega/k ω / k , the other at most a ω a\omega aω . k k k and λ \lambda λ . k = 2 π / λ k = 2\pi/\lambda k = 2 π / λ . A larger k k k is a shorter wave. Grams in μ \mu μ . Use kg/m. Celsius in T \sqrt{T} T . Use kelvin. Check yourself Is a wave on a plucked string transverse or longitudinal? Stuck? Show a hint Show the answerA wave has k = 2 π rad/m k = 2\pi\ \text{rad/m} k = 2 π rad/m and ω = 10 π rad/s \omega = 10\pi\ \text{rad/s} ω = 10 π rad/s . Find its speed. Stuck? Show a hint Show the answerThe tension in a string is made nine times as large. What happens to the wave speed? Stuck? Show a hint Show the answerWhy does pressure alone not change the speed of sound in a gas? Stuck? Show a hint Show the answer