A brief note on Reflection and Mirrors . Read it before a test. Try each question at the end before you open its answer.
The big ideas The angle of incidence equals the angle of reflection, both measured from the normal . A plane mirror gives a virtual, upright image of the same size, as far behind the mirror as the object is in front, with left and right swapped. For a spherical mirror, f = R 2 f = \dfrac{R}{2} f = 2 R : the focus is half way between the pole and the centre of curvature. A concave mirror gives real images (object beyond F F F ) or a larger virtual image (object inside F F F ). A convex mirror always gives a smaller, virtual, upright image between P P P and F F F . Mirror formula 1 v + 1 u = 1 f \dfrac{1}{v} + \dfrac{1}{u} = \dfrac{1}{f} v 1 + u 1 = f 1 , and m = h ′ h = − v u m = \dfrac{h'}{h} = -\dfrac{v}{u} m = h h ′ = − u v . The facts at a glance Concave mirror: object Image Nature Beyond C C C Between F F F and C C C Real, inverted, smaller At C C C At C C C Real, inverted, same size Between C C C and F F F Beyond C C C Real, inverted, larger Inside F F F Behind the mirror Virtual, upright, larger
Sign Concave mirror Convex mirror u u u negative negative f f f negative positive v v v for a real image negative (never real)
A worked example An object 3 cm 3\ \text{cm} 3 cm tall stands 40 cm 40\ \text{cm} 40 cm from a concave mirror of focal length 16 cm 16\ \text{cm} 16 cm . Find the image.
The signs. u = − 40 cm u = -40\ \text{cm} u = − 40 cm , f = − 16 cm f = -16\ \text{cm} f = − 16 cm . The image. 1 v = − 1 16 cm + 1 40 cm = − 5 + 2 80 cm = − 3 80 cm \dfrac{1}{v} = -\dfrac{1}{16\ \text{cm}} + \dfrac{1}{40\ \text{cm}} = \dfrac{-5 + 2}{80\ \text{cm}} = -\dfrac{3}{80\ \text{cm}} v 1 = − 16 cm 1 + 40 cm 1 = 80 cm − 5 + 2 = − 80 cm 3 , so v = − 26.7 cm v = -26.7\ \text{cm} v = − 26.7 cm . The size. m = − v u = − 0.667 m = -\dfrac{v}{u} = -0.667 m = − u v = − 0.667 , so h ′ = − 0.667 × 3 cm = − 2 cm h' = -0.667 \times 3\ \text{cm} = -2\ \text{cm} h ′ = − 0.667 × 3 cm = − 2 cm . The image is 26.7 cm 26.7\ \text{cm} 26.7 cm in front of the mirror: real, inverted and 2 cm 2\ \text{cm} 2 cm tall. The object is beyond C C C ( 32 cm 32\ \text{cm} 32 cm ), as the table says.
Practice with new numbers
A program to try The program uses the mirror formula for any mirror, and says what the image is like.
Read it, then run it. It repeats the worked example.
1. Change f = -16 to f = 16, a convex mirror. What changes?
2. Try u = -10 with the concave mirror. Which line of the table is it?
Mistakes to avoid Measuring angles from the mirror surface. The laws use the normal. Giving a concave mirror a positive f f f . In this convention it is negative. Dropping the minus sign in m = − v u m = -\dfrac{v}{u} m = − u v . It is part of the mirror's formula. 'A concave mirror always gives a real image.' Not inside F F F . Check yourself A ray makes 35 ∘ 35^\circ 3 5 ∘ with the surface of a plane mirror. What is the angle of reflection? Stuck? Show a hint Show the answerA concave mirror has R = 46 cm R = 46\ \text{cm} R = 46 cm . Where should a bulb go for a parallel beam? Stuck? Show a hint Show the answerWhich mirror can only give virtual images? Stuck? Show a hint Show the answerA concave mirror gives m = + 2.5 m = +2.5 m = + 2.5 . What is the image like, and where is the object? Stuck? Show a hint Show the answer