A brief note on Purification and Analysis of Organic Compounds . Read it before a test. Try each question at the end before you open its answer.
Purification Sublimation: a solid goes to vapour and back, leaving impurities behind. Crystallisation: hot saturated solution, then cooling. The impurities stay in the mother liquor. Simple distillation: a large gap in boiling points. Fractional: a small gap, with a column. Reduced pressure: for a liquid that decomposes. Steam: for a liquid that does not mix with water. Extraction: moves a compound into a solvent that does not mix with water. Chromatography: R f = d s d f R_f = \dfrac{d_s}{d_f} R f = d f d s , the distance moved by the substance over the distance moved by the solvent front. It is never more than 1. Tests for the elements Carbon: carbon dioxide turns lime water milky. Hydrogen: water turns white copper sulphate blue. Sodium fusion makes CN, S and X ions. Boil with nitric acid before silver nitrate. Nitrogen: Prussian blue. Sulphur: black PbS or violet. Both together: blood red. Halogens: white (Cl), pale yellow (Br), yellow (I). Phosphorus: yellow with ammonium molybdate. Quantitative methods Liebig: % C = 12 44 × m C O 2 m × 100 \%\text{C} = \tfrac{12}{44} \times \tfrac{m_{CO_2}}{m} \times 100 % C = 44 12 × m m C O 2 × 100 and % H = 2 18 × m H 2 O m × 100 \%\text{H} = \tfrac{2}{18} \times \tfrac{m_{H_2O}}{m} \times 100 % H = 18 2 × m m H 2 O × 100 . Dumas: % N = 28 V 22400 m × 100 \%\text{N} = \tfrac{28 V}{22400\, m} \times 100 % N = 22400 m 28 V × 100 with V V V at STP in mL. Kjeldahl: % N = 1.4 M b V m \%\text{N} = \tfrac{1.4\, M b V}{m} % N = m 1.4 M bV . It fails for nitro, azo and ring nitrogen. Carius: halogen as AgX, sulphur as BaSO4, phosphorus as Mg 2 P 2 O 7 \text{Mg}_2\text{P}_2\text{O}_7 Mg 2 P 2 O 7 . Oxygen by difference. Empirical formula: percentage over atomic mass, then divide by the smallest. A worked example A 0.45 g 0.45\ \text{g} 0.45 g sample gives 1.10 g 1.10\ \text{g} 1.10 g of carbon dioxide and 0.27 g 0.27\ \text{g} 0.27 g of water. Find the per cent of carbon and hydrogen.
Carbon. 12 44 × 1.10 0.45 × 100 = 66.7 \dfrac{12}{44} \times \dfrac{1.10}{0.45} \times 100 = 66.7 44 12 × 0.45 1.10 × 100 = 66.7 . Hydrogen. 2 18 × 0.27 0.45 × 100 = 6.67 \dfrac{2}{18} \times \dfrac{0.27}{0.45} \times 100 = 6.67 18 2 × 0.45 0.27 × 100 = 6.67 . Practice with new numbers
A program to try The program finds the per cent of carbon, hydrogen and sulphur from the mass of each product, with one short function.
Run it. Which element is present in the smallest per cent?
1. Add a line for nitrogen found as ammonia, with an atomic mass of 14 and a molar mass of 17 for NH 3 \text{NH}_3 NH 3 . Does it make sense?
Mistakes to avoid All the carbon dioxide counted as carbon. Only 12 parts in 44 are carbon. Silver nitrate before nitric acid. Cyanide and sulphide give false precipitates. Forgetting basicity in Kjeldahl's formula. Sulphuric acid supplies two hydrogen ions. Rounding a ratio of 1.5 to 1 or 2. Multiply by 2 instead. Measuring Rf from the bottom of the plate. Measure from the starting line. Check yourself Which method purifies a solid that sublimes, such as camphor? Stuck? Show a hint Show the answerA compound gives a blood red colour with iron(III) chloride. Which two elements does it hold? Stuck? Show a hint Show the answerWhy is Kjeldahl's method no good for a nitro compound? Stuck? Show a hint Show the answerA compound has 80 % carbon and 20 % hydrogen. What is its empirical formula? Stuck? Show a hint Show the answer