A brief note on Classification, Nomenclature and Isomerism . Read it before a test. Try each question at the end before you open its answer.
Shapes of carbon compounds Carbon forms four bonds, and joins to itself in chains and rings. s p 3 sp^3 s p 3 : tetrahedral, 109.5 degrees. s p 2 sp^2 s p 2 : planar, 120 degrees. s p sp s p : linear, 180 degrees. Every bond has one sigma bond . A double bond adds one pi bond , and a triple bond adds two. Bond lengths: C-C 154 pm, C=C 134 pm, C≡C 120 pm. Writing a structure Complete: every atom and bond. Condensed: CH 3 CH(OH)CH 2 CH 3 \text{CH}_{3}\text{CH(OH)CH}_{2}\text{CH}_{3} CH 3 CH(OH)CH 2 CH 3 . Bond-line: corners and ends are carbons, and the hydrogen atoms on carbon are not drawn. Wedge and dash: a wedge comes towards you, a dash goes away. Classification Acyclic (open chain) or cyclic . Cyclic: alicyclic , aromatic or heterocyclic . Saturated (single bonds only) or unsaturated . A homologous series has one functional group and one general formula, and each member differs by CH 2 \text{CH}_{2} CH 2 , 14 u. Alkanes C n H 2 n + 2 \text{C}_n\text{H}_{2n+2} C n H 2 n + 2 , alkenes C n H 2 n \text{C}_n\text{H}_{2n} C n H 2 n , alkynes C n H 2 n − 2 \text{C}_n\text{H}_{2n-2} C n H 2 n − 2 . Naming Word roots: meth, eth, prop, but, pent, hex, hept, oct, non, dec. Longest chain , holding the principal group and the multiple bonds. Lowest locants at the first point of difference: principal group first, then multiple bonds, then branches. Branches in alphabetical order, ignoring di and tri. Seniority: acid, ester, amide, nitrile, aldehyde, ketone, alcohol, amine, alkene, alkyne. Suffixes: -oic acid , -oate , -amide , -nitrile , -al , -one , -ol , -amine , -ene , -yne . Prefixes only: chloro, bromo, nitro, methoxy, alkyl. Isomerism Structural: chain, position, functional group, metamerism, tautomerism. Geometrical: each end of a double bond has two different groups, giving cis and trans. Optical: a chiral carbon holds four different groups. Enantiomers turn polarised light in opposite directions. Degrees of unsaturation: 2 C + 2 + N − H − X 2 \dfrac{2\text{C} + 2 + \text{N} - \text{H} - \text{X}}{2} 2 2 C + 2 + N − H − X . Up to 2 n 2^n 2 n stereoisomers for n different stereocentres. A worked example Name CH 3 CH(CH 3 )CH 2 CH(OH)CH 3 \text{CH}_{3}\text{CH(CH}_{3}\text{)CH}_{2}\text{CH(OH)CH}_{3} CH 3 CH(CH 3 )CH 2 CH(OH)CH 3 .
Chain. The longest chain has five carbons: pentane. Principal group. The alcohol gives the suffix -ol . Number from the right, so that OH is on carbon 2, not 4. Branch. The methyl group is then on carbon 4. Name. 4-methylpentan-2-ol . Practice with new numbers
A program to try The program builds the name for methyl groups on a chain, with the lowest locants.
Run it. Compare each name with the rules above.
1. Add print(name_methyl(8, [2, 7])). Predict the name first.
Mistakes to avoid Not taking the longest chain. Choosing the lowest sum of locants, not the lowest at the first difference. Forgetting that the principal group comes before the multiple bonds and the branches. Saying every alkene has cis and trans forms. Each end needs two different groups. Calling a carbon chiral when two of its groups are the same.