A brief note on Lenses, Prisms and Dispersion . Read it before a test. Try each question at the end before you open its answer.
The thin lens Signs (New Cartesian): light goes left to right, distances are measured from the optical centre, and a real object has u < 0 u < 0 u < 0 . Thin lens formula: 1 v − 1 u = 1 f \dfrac{1}{v} - \dfrac{1}{u} = \dfrac{1}{f} v 1 − u 1 = f 1 . Magnification: m = v u m = \dfrac{v}{u} m = u v . A negative m m m is an inverted image. Real is positive (A-Level, IB, AP): 1 u + 1 v = 1 f \dfrac{1}{u} + \dfrac{1}{v} = \dfrac{1}{f} u 1 + v 1 = f 1 and m = − v u m = -\dfrac{v}{u} m = − u v . Lens maker's formula: 1 f = ( n − 1 ) ( 1 R 1 − 1 R 2 ) \dfrac{1}{f} = (n-1)\left(\dfrac{1}{R_1} - \dfrac{1}{R_2}\right) f 1 = ( n − 1 ) ( R 1 1 − R 2 1 ) . A biconvex lens has R 1 > 0 R_1 > 0 R 1 > 0 and R 2 < 0 R_2 < 0 R 2 < 0 . In a medium: replace n n n by n g n m \dfrac{n_g}{n_m} n m n g . A concave lens always gives a virtual, upright, smaller image of a real object. Power and combinations Power: P = 1 f P = \dfrac{1}{f} P = f 1 , with f f f in metre. The unit is the dioptre. In contact: P = P 1 + P 2 P = P_1 + P_2 P = P 1 + P 2 and m = m 1 m 2 m = m_1m_2 m = m 1 m 2 . A gap d d d : P = P 1 + P 2 − d P 1 P 2 P = P_1 + P_2 - dP_1P_2 P = P 1 + P 2 − d P 1 P 2 . The pair is afocal when d = f 1 + f 2 d = f_1 + f_2 d = f 1 + f 2 . Direct method: the image of the first lens is the object of the second, u 2 = v 1 − d u_2 = v_1 - d u 2 = v 1 − d . The prism and dispersion Angles: r 1 + r 2 = A r_1 + r_2 = A r 1 + r 2 = A and δ = i + e − A \delta = i + e - A δ = i + e − A . Minimum deviation: i = e i = e i = e and n = sin A + δ m 2 sin A 2 n = \dfrac{\sin\frac{A + \delta_m}{2}}{\sin\frac{A}{2}} n = sin 2 A sin 2 A + δ m . Thin prism: δ = ( n − 1 ) A \delta = (n-1)A δ = ( n − 1 ) A . Dispersive power: ω = n b − n r n y − 1 \omega = \dfrac{n_b - n_r}{n_y - 1} ω = n y − 1 n b − n r . Violet bends most. A flat sheet does not disperse. Sky: scattering ∝ 1 λ 4 \propto \dfrac{1}{\lambda^4} ∝ λ 4 1 , so the sky is blue and the sunset red. The primary bow is at 42 ∘ 42^\circ 4 2 ∘ (red outside), the secondary at 51 ∘ 51^\circ 5 1 ∘ (red inside). A worked example A thin convex lens has f = 12 cm f = 12\ \text{cm} f = 12 cm . An object is 20 cm 20\ \text{cm} 20 cm in front. Find the image.
Distance. v = u f u + f = ( − 20 ) ( 12 ) − 20 + 12 cm = 30 cm v = \dfrac{uf}{u + f} = \dfrac{(-20)(12)}{-20 + 12}\ \text{cm} = 30\ \text{cm} v = u + f u f = − 20 + 12 ( − 20 ) ( 12 ) cm = 30 cm . Magnification. m = 30 − 20 = − 1.5 m = \dfrac{30}{-20} = -1.5 m = − 20 30 = − 1.5 . The image is real, inverted and larger. Practise with new numbers
Check yourself What is the power of a lens of focal length − 25 cm -25\ \text{cm} − 25 cm ? Stuck? Show a hint Show the answerA thin prism of angle 6 ∘ 6^\circ 6 ∘ and index 1.5 1.5 1.5 deviates a ray by how much? Stuck? Show a hint Show the answerWhy does a prism split white light and a flat sheet of glass does not? Stuck? Show a hint Show the answerSources NCERT Physics Part II (Class 12), Chapter 9. OpenStax University Physics Volume 3, Chapters 1 and 2.