A brief note on Diffraction, Gratings and Resolving Power . Read it before a test. Try each question at the end before you open its answer.
Single slit Dark places: a sin θ = n λ a\sin\theta = n\lambda a sin θ = nλ , with n = ± 1 , ± 2 , … n = \pm1, \pm2, \dots n = ± 1 , ± 2 , … The centre is not dark. Central maximum: w = 2 λ D a w = \dfrac{2\lambda D}{a} w = a 2 λ D . It is twice as wide as each weak maximum. Intensity: I / I 0 = ( sin α / α ) 2 I/I_0 = (\sin\alpha/\alpha)^2 I / I 0 = ( sin α / α ) 2 , with α = π a sin θ / λ \alpha = \pi a\sin\theta/\lambda α = π a sin θ / λ . The weak maxima have 0.047 0.047 0.047 , 0.016 0.016 0.016 and 0.008 0.008 0.008 of the centre. Narrower slit, wider pattern. Fresnel distance: z F = a 2 / λ z_F = a^2/\lambda z F = a 2 / λ . Ray optics holds up to about z F z_F z F . Double slit with diffraction, and the grating Fringes inside the central maximum: orders m < d / a m < d/a m < d / a . A missing order has m = n d / a m = n\,d/a m = n d / a . Grating: d sin θ = m λ d\sin\theta = m\lambda d sin θ = mλ , with d = 1 / N 1 d = 1/N_1 d = 1/ N 1 . The highest order has m < d / λ m < d/\lambda m < d / λ . More slits: narrower, brighter principal maxima. White light: the zero order is white. Each higher order is a spectrum, with violet inside and red outside. Orders 2 and 3 overlap. Resolving power Circular aperture: first dark ring at 1.22 λ / D 1.22\lambda/D 1.22 λ / D . Rayleigh limit: θ min = 1.22 λ / D \theta_{\min} = 1.22\lambda/D θ m i n = 1.22 λ / D . Resolving power: 1 / θ min 1/\theta_{\min} 1/ θ m i n . It rises with a bigger aperture and a shorter wavelength. Microscope: d min = 0.61 λ / NA d_{\min} = 0.61\lambda/\text{NA} d m i n = 0.61 λ / NA . Grating: R = λ / Δ λ = m N R = \lambda/\Delta\lambda = mN R = λ /Δ λ = m N . A worked example A slit 0.25 0.25 0.25 mm wide is lit by light of wavelength 650 650 650 nm. The screen is 1.20 1.20 1.20 m away. Find the width of the central maximum.
First minimum. y 1 = λ D a = 650 × 10 − 9 m × 1.20 m 0.25 × 10 − 3 m = 3.12 mm y_1 = \dfrac{\lambda D}{a} = \dfrac{650 \times 10^{-9}\ \text{m} \times 1.20\ \text{m}}{0.25 \times 10^{-3}\ \text{m}} = 3.12\ \text{mm} y 1 = a λ D = 0.25 × 1 0 − 3 m 650 × 1 0 − 9 m × 1.20 m = 3.12 mm . The width. w = 2 y 1 = 6.24 mm w = 2y_1 = 6.24\ \text{mm} w = 2 y 1 = 6.24 mm . Practise with new numbers
Check yourself A grating has 6000 6000 6000 lines in each centimetre. Light of 650 650 650 nm falls on it. What is the highest order? Stuck? Show a hint Show the answerWhy can a bigger telescope tell apart two closer stars? Stuck? Show a hint Show the answerThe slit of a single-slit experiment is made narrower. What happens to the pattern? Stuck? Show a hint Show the answerSources OpenStax, University Physics Volume 3, Chapter 4 (Diffraction). NCERT Physics Class 12, Chapter 10 (Wave Optics).