A brief note on Inorganic Qualitative Analysis . Read it before a test. Try each question at the end before you open its answer.
Anions Dilute sulphuric acid: carbonate (carbon dioxide, milky lime water), sulphide (rotten eggs, black lead acetate paper), sulphite (choking smell, green dichromate paper), nitrite (brown fumes), acetate (vinegar). Concentrated sulphuric acid: chloride (white fumes with ammonia), bromide (reddish brown vapour), iodide (violet vapour), nitrate (brown fumes with copper). Brown ring test for nitrate: iron(II) sulphate, then concentrated acid slowly down the wall. Sulphate: barium chloride gives a white precipitate that stays in dilute hydrochloric acid. Silver halides: white, pale yellow, yellow. Cations Zero NH 4 + \text{NH}_{4}^{+} NH 4 + : sodium hydroxide, ammonia gas. I Pb 2 + \text{Pb}^{2+} Pb 2 + : dilute HCl. II Cu 2 + \text{Cu}^{2+} Cu 2 + : hydrogen sulphide in acid. III Fe 3 + \text{Fe}^{3+} Fe 3 + , Al 3 + \text{Al}^{3+} Al 3 + : ammonium chloride and ammonium hydroxide. IV Zn, Ni, Co, Mn: hydrogen sulphide in ammonia. V Ca, Ba: ammonium carbonate. VI Mg: disodium hydrogenphosphate. Iron(III): Prussian blue, blood red with thiocyanate. Copper: deep blue with excess ammonia. Nickel: rosy red with DMG. Zinc and aluminium dissolve in excess sodium hydroxide. Calcium is brick red and barium apple green in a flame. Why it works A precipitate forms when Q > K s p Q > K_{sp} Q > K s p . [ S 2 − ] [\text{S}^{2-}] [ S 2 − ] is proportional to 1 / [ H + ] 2 1 / [\text{H}^+]^2 1/ [ H + ] 2 . In acid only copper sulphide forms. In ammonia, zinc, nickel, cobalt and manganese sulphides form too. Ammonium chloride lowers [ OH − ] [\text{OH}^-] [ OH − ] , so only iron(III) and aluminium hydroxides form in group III. A worked example Sodium chloride, 1.17 g, is treated with excess silver nitrate. What mass of silver chloride forms?
Moles. 1.17 58.5 = 0.0200 mol \dfrac{1.17}{58.5} = 0.0200\ \text{mol} 58.5 1.17 = 0.0200 mol . Mass. 0.0200 × 143.5 = 2.87 g 0.0200 \times 143.5 = 2.87\ \text{g} 0.0200 × 143.5 = 2.87 g . Practice with new numbers
A program to try The program follows a mixture of cations through the group scheme.
Run it. Which group catches two cations?
1. Change the mixture to ["Pb2+", "Al3+", "Mn2+", "Ca2+"] and run it again.
Mistakes to avoid Testing for ammonium after the group III reagent. It contains ammonium. Naming an anion from the first gas. Carbon dioxide and sulphur dioxide both turn lime water milky. Forgetting the dilute acid in the barium chloride test for sulphate. Check yourself Which gas gives a green dichromate paper? Stuck? Show a hint Show the answerWhich cation gives a blood red colour with thiocyanate? Stuck? Show a hint Show the answerWhy does hydrogen sulphide in acid precipitate copper sulphide only? Stuck? Show a hint Show the answerWhat do you see in the brown ring test? Stuck? Show a hint Show the answer