A brief note on Detecting Elements and Groups in Organic Compounds . Read it before a test. Try each question at the end before you open its answer.
Carbon and hydrogen Heat the dry compound with dry copper(II) oxide. Carbon dioxide turns lime water milky. Water turns white copper(II) sulphate blue. Too much carbon dioxide clears the lime water again. Fuse the compound with sodium, plunge it into water, boil and filter. Sodium makes NaCN \text{NaCN} NaCN , Na 2 S \text{Na}_{2}\text{S} Na 2 S and NaX \text{NaX} NaX . With both N and S and little sodium it makes NaSCN \text{NaSCN} NaSCN . Nitrogen: iron(II) sulphate, warm, then acid. Prussian blue, Fe 4 [ Fe ( CN ) 6 ] 3 \text{Fe}_{4}[\text{Fe}(\text{CN})_{6}]_{3} Fe 4 [ Fe ( CN ) 6 ] 3 . Sulphur: sodium nitroprusside gives violet. Acetic acid and lead acetate give black PbS \text{PbS} PbS . Nitrogen and sulphur together: blood red with iron(III) chloride. Halogens: boil with nitric acid, then silver nitrate. White (dissolves in dilute ammonia solution), pale yellow (sparingly), yellow (does not). Hydrazine and diazonium salts give no Prussian blue. Functional groups Double bond: bromine water and Baeyer's reagent lose their colour. Phenol: violet with neutral iron(III) chloride. White tribromophenol with bromine water. Carbonyl: orange 2,4-DNP precipitate. Aldehyde: silver mirror, pink Schiff's reagent. Aliphatic aldehyde: red Fehling's precipitate. Iodoform: yellow with CH 3 CO- \text{CH}_{3}\text{CO}\text{-} CH 3 CO - or CH 3 CH ( OH ) - \text{CH}_{3}\text{CH}(\text{OH})\text{-} CH 3 CH ( OH ) - . Acid: effervescence with sodium hydrogencarbonate. Primary amine: carbylamine smell. Primary aromatic amine: orange-red azo dye. A worked example A chlorine compound of mass 0.850 g 0.850\ \text{g} 0.850 g gives 0.861 g 0.861\ \text{g} 0.861 g of silver chloride. What is the percentage of chlorine?
Moles. 0.861 143.5 = 6.00 mmol \dfrac{0.861}{143.5} = 6.00\ \text{mmol} 143.5 0.861 = 6.00 mmol . Mass of chlorine. 6.00 × 35.5 = 213 mg 6.00 \times 35.5 = 213\ \text{mg} 6.00 × 35.5 = 213 mg . Percentage. 0.213 0.850 × 100 = 25.1 % \dfrac{0.213}{0.850} \times 100 = 25.1\ \% 0.850 0.213 × 100 = 25.1 % . Practice with new numbers
A program to try The program works out the percentage of a halogen from the mass of its silver halide.
Run it. Then change name to "iodine" and run it again.
1. Which halogen gives the larger percentage for the same mass of precipitate?
Mistakes to avoid Skipping the nitric acid before silver nitrate. Using Fehling's solution for benzaldehyde. Reading a blood red colour as nitrogen alone. It shows nitrogen and sulphur together. Calling every alcohol an iodoform positive. Check yourself What does a violet colour with sodium nitroprusside show? Stuck? Show a hint Show the answerWhich reagent separates an aldehyde from a ketone? Stuck? Show a hint Show the answerHow can sodium hydrogencarbonate tell benzoic acid from phenol? Stuck? Show a hint Show the answerA precipitate is white and dissolves in dilute ammonia solution. Which halogen is it? Stuck? Show a hint Show the answer