A brief note on Groups 13 and 14 Compared . Read it before a test. Try each question at the end before you open its answer.
The inert pair effect The heavy elements prefer the state two lower: Tl + ^+ + , Pb 2 + ^{2+} 2 + . Cause: poor shielding by d d d and f f f electrons, and weak bonds of large atoms. Tl(III), Pb(IV) oxidise. Sn(II), Ge(II) reduce. The lower state is more ionic. PbCl 4 \text{PbCl}_{4} PbCl 4 loses chlorine. PbBr 4 \text{PbBr}_{4} PbBr 4 and PbI 4 \text{PbI}_{4} PbI 4 do not exist. TlI 3 _3 3 is Tl + ^+ + I 3 − _3^- 3 − . log K = n E ∘ / 0.05916 \log K = nE^\circ/0.05916 log K = n E ∘ /0.05916 at 298 K. A reaction goes if E c e l l ∘ E^\circ_{cell} E ce l l ∘ is positive. Hydrides Electron deficient: B 2 H 6 \text{B}_{2}\text{H}_{6} B 2 H 6 , ( AlH 3 ) n (\text{AlH}_{3})\text{n} ( AlH 3 ) n . Electron precise: CH 4 \text{CH}_{4} CH 4 , SiH 4 \text{SiH}_{4} SiH 4 . Stability falls down the groups. LiAlH 4 \text{LiAlH}_{4} LiAlH 4 and NaBH 4 \text{NaBH}_{4} NaBH 4 hold tetrahedral [ AlH 4 ] − [\text{AlH}_{4}]^{-} [ AlH 4 ] − and [ BH 4 ] − [\text{BH}_{4}]^{-} [ BH 4 ] − . LiAlH 4 + 4 H 2 O → LiOH + Al ( OH ) 3 + 4 H 2 \text{LiAlH}_{4} + 4\text{H}_{2}\text{O} \to \text{LiOH} + \text{Al}(\text{OH})_{3} + 4\text{H}_{2} LiAlH 4 + 4 H 2 O → LiOH + Al ( OH ) 3 + 4 H 2 . SiH 4 \text{SiH}_{4} SiH 4 burns in air and is hydrolysed in alkaline water. Mg 2 Si + 4 HCl → 2 MgCl 2 + SiH 4 \text{Mg}_{2}\text{Si} + 4\text{HCl} \to 2\text{MgCl}_{2} + \text{SiH}_{4} Mg 2 Si + 4 HCl → 2 MgCl 2 + SiH 4 . Halides Lewis acid strength: BF 3 < BCl 3 < BBr 3 < BI 3 \text{BF}_3 < \text{BCl}_3 < \text{BBr}_3 < \text{BI}_3 BF 3 < BCl 3 < BBr 3 < BI 3 , because of back bonding. CCl 4 \text{CCl}_{4} CCl 4 is not hydrolysed. SiCl 4 + 4 H 2 O → Si ( OH ) 4 + 4 HCl \text{SiCl}_{4} + 4\text{H}_{2}\text{O} \to \text{Si}(\text{OH})_{4} + 4\text{HCl} SiCl 4 + 4 H 2 O → Si ( OH ) 4 + 4 HCl . SiF 4 \text{SiF}_{4} SiF 4 gives [ SiF 6 ] 2 − [\text{SiF}_{6}]^{2-} [ SiF 6 ] 2 − . Al 2 Cl 6 \text{Al}_{2}\text{Cl}_{6} Al 2 Cl 6 has two-centre bridges. Diborane has three-centre bridges. Oxides and carbides Acidic: B 2 O 3 \text{B}_{2}\text{O}_{3} B 2 O 3 , CO 2 \text{CO}_{2} CO 2 , SiO 2 \text{SiO}_{2} SiO 2 , GeO 2 \text{GeO}_{2} GeO 2 . Amphoteric: Al 2 O 3 \text{Al}_{2}\text{O}_{3} Al 2 O 3 , SnO 2 \text{SnO}_{2} SnO 2 , PbO 2 \text{PbO}_{2} PbO 2 , PbO. Basic: In 2 O 3 \text{In}_{2}\text{O}_{3} In 2 O 3 , Tl 2 O \text{Tl}_{2}\text{O} Tl 2 O . Neutral: CO. Red lead Pb 3 O 4 \text{Pb}_{3}\text{O}_{4} Pb 3 O 4 is 2 PbO ⋅ PbO 2 2\text{PbO}\cdot \text{PbO}_{2} 2 PbO ⋅ PbO 2 . Dilute nitric acid gives PbO 2 \text{PbO}_{2} PbO 2 and lead nitrate. CaC 2 \text{CaC}_{2} CaC 2 gives acetylene, Al 4 C 3 \text{Al}_{4}\text{C}_{3} Al 4 C 3 gives methane, Mg 2 C 3 \text{Mg}_{2}\text{C}_{3} Mg 2 C 3 gives propyne. SiC and B 4 C \text{B}_{4}\text{C} B 4 C are hard covalent carbides. A worked example Find log K \log K log K for a reaction with a cell potential of 0.92 V 0.92\ \text{V} 0.92 V and two electrons.
Put in the numbers. log K = 2 × 0.92 / 0.05916 \log K = 2 \times 0.92 / 0.05916 log K = 2 × 0.92/0.05916 . Work out. log K = 31.1 \log K = 31.1 log K = 31.1 , so the reaction runs to completion. Practice with new numbers
A program to try Run it. Does the first line agree with the practice rule that a small positive potential gives a small log K?
1. Add -0.10 to the list. What sign does log K have, and what does it mean?
Mistakes to avoid Saying that Sn(IV) is a strong oxidiser. Pb(IV) is. Saying that BF 3 _3 3 is the strongest of the boron halides as a Lewis acid. It is the weakest. Saying that CCl 4 _4 4 is hydrolysed. It is not. Calling PbO 2 _2 2 or SnO 2 _2 2 acidic. They are amphoteric. Check yourself Why is thallium(I) more stable than thallium(III)? Stuck? Show a hint Show the answerWhy is SiCl 4 _4 4 hydrolysed but CCl 4 _4 4 is not? Stuck? Show a hint Show the answerWhat gas comes from water and aluminium carbide? Stuck? Show a hint Show the answerName the amphoteric oxides of group 14. Stuck? Show a hint Show the answerSources OpenStax, Chemistry 2e, Chapter 18. NCERT Chemistry for Class 11, the chapter The p-Block Elements (older edition). Atkins and Shriver, Inorganic Chemistry, the chapters on the group 13 and group 14 elements.