A brief note on Oxygen, Ozone and Sulphur . Read it before a test. Try each question at the end before you open its answer.
The group and oxygen Group 16 is n s 2 n p 4 ns^2np^4 n s 2 n p 4 : O, S (non-metals), Se, Te (metalloids), Po (metal). States − 2 -2 − 2 , + 2 +2 + 2 , + 4 +4 + 4 , + 6 +6 + 6 . Oxygen is small, has no d orbitals, so its covalency is at most 2. It forms hydrogen bonds, and O 2 \text{O}_{2} O 2 is paramagnetic. H 2 E \text{H}_{2}\text{E} H 2 E : angle falls from 104.5° ( H 2 O \text{H}_{2}\text{O} H 2 O ) to about 90°. Acidity and reducing power rise, and stability falls, down the group. Oxygen: 2 KClO 3 → MnO 2 , heat 2 KCl + 3 O 2 2\text{KClO}_{3}\ \xrightarrow{\text{MnO}_{2},\ \ \text{heat}}\ 2\text{KCl}\ +\ 3\text{O}_{2} 2 KClO 3 MnO 2 , heat 2 KCl + 3 O 2 , and from liquid air in industry. Oxides: basic (metals), acidic (non-metals), amphoteric ( Al 2 O 3 \text{Al}_{2}\text{O}_{3} Al 2 O 3 , ZnO \text{ZnO} ZnO ), neutral ( CO \text{CO} CO , NO \text{NO} NO , N 2 O \text{N}_{2}\text{O} N 2 O ). Peroxide O 2 2 − \text{O}_{2}^{2-} O 2 2 − , superoxide O 2 − \text{O}_{2}^{-} O 2 − . Ozone and sulphur Ozone: 3 O 2 ⇌ 2 O 3 3\text{O}_{2}\ \rightleftharpoons \ 2\text{O}_{3} 3 O 2 ⇌ 2 O 3 in a silent discharge, bent at 117°, a strong oxidiser. PbS + 4 O 3 → PbSO 4 + 4 O 2 \text{PbS}\ +\ 4\text{O}_{3}\ \rightarrow \ \text{PbSO}_{4}\ +\ 4\text{O}_{2} PbS + 4 O 3 → PbSO 4 + 4 O 2 . CFCs give chlorine atoms, which catalyse the loss of ozone in the stratosphere. Sulphur: rhombic (stable below 369 K) and monoclinic (above 369 K), both S 8 \text{S}_{8} S 8 crowns. SO 2 \text{SO}_{2} SO 2 : bent at about 119°, acidic, a reducing agent, a temporary bleach, and a cause of acid rain. It turns acidified dichromate green. Sulphuric acid Contact process: 2 SO 2 + O 2 ⇌ 2 SO 3 2\text{SO}_{2}\ +\ \text{O}_{2}\ \rightleftharpoons \ 2\text{SO}_{3} 2 SO 2 + O 2 ⇌ 2 SO 3 over V 2 O 5 \text{V}_{2}\text{O}_{5} V 2 O 5 , about 720 K and 1 to 2 bar. Absorb SO 3 \text{SO}_{3} SO 3 in concentrated acid to give oleum, then dilute. Concentrated H 2 SO 4 \text{H}_{2}\text{SO}_{4} H 2 SO 4 is a dehydrating agent, an oxidiser when hot ( Cu + 2 H 2 SO 4 → CuSO 4 + SO 2 + 2 H 2 O \text{Cu}\ +\ 2\text{H}_{2}\text{SO}_{4}\ \rightarrow \ \text{CuSO}_{4}\ +\ \text{SO}_{2}\ +\ 2\text{H}_{2}\text{O} Cu + 2 H 2 SO 4 → CuSO 4 + SO 2 + 2 H 2 O ) and non-volatile. Oxoacids: H 2 SO 3 \text{H}_{2}\text{SO}_{3} H 2 SO 3 + 4 +4 + 4 , H 2 S 2 O 6 \text{H}_{2}\text{S}_{2}\text{O}_{6} H 2 S 2 O 6 + 5 +5 + 5 , and H 2 SO 4 \text{H}_{2}\text{SO}_{4} H 2 SO 4 , H 2 S 2 O 7 \text{H}_{2}\text{S}_{2}\text{O}_{7} H 2 S 2 O 7 , H 2 SO 5 \text{H}_{2}\text{SO}_{5} H 2 SO 5 , H 2 S 2 O 8 \text{H}_{2}\text{S}_{2}\text{O}_{8} H 2 S 2 O 8 at + 6 +6 + 6 . The last two have O-O links. A worked example Find the volume of sulphur dioxide from 8.0 kg 8.0\ \text{kg} 8.0 kg of sulphur at 273 K 273\ \text{K} 273 K and 1 atm 1\ \text{atm} 1 atm .
Moles. 8000 g 32 g/mol = 250 mol \dfrac{8000\ \text{g}}{32\ \text{g/mol}} = 250\ \text{mol} 32 g/mol 8000 g = 250 mol . Ratio. One mole of sulphur gives one mole of sulphur dioxide. Volume. 250 mol × 22.4 L/mol = 5600 L 250\ \text{mol} \times 22.4\ \text{L/mol} = 5600\ \text{L} 250 mol × 22.4 L/mol = 5600 L . Practice with new numbers
A program to try The program follows sulphur through the contact process to sulphuric acid.
Run it. How much 98 percent acid do 16 tonnes of sulphur give?
1. Change overall_yield = 0.95 to 0.90. What happens to the acid?
Mistakes to avoid Adding water to concentrated sulphuric acid. Add the acid to the water. Saying that sulphur dioxide bleaches by oxidation. It bleaches by reduction. Absorbing sulphur trioxide in water. It makes a mist. Use concentrated acid. Giving sulphur + 8 +8 + 8 in a peroxo acid. The peroxide oxygen atoms are − 1 -1 − 1 . Check yourself Which oxide of the list CO \text{CO} CO , Al 2 O 3 \text{Al}_{2}\text{O}_{3} Al 2 O 3 , SO 2 \text{SO}_{2} SO 2 is amphoteric? Stuck? Show a hint Show the answerWhat colour change shows sulphur dioxide with acidified dichromate? Stuck? Show a hint Show the answerWhy is a catalyst used in the contact process? Stuck? Show a hint Show the answerWhat is the state of sulphur in H 2 S 2 O 8 \text{H}_{2}\text{S}_{2}\text{O}_{8} H 2 S 2 O 8 ? Stuck? Show a hint Show the answerSources NCERT, Chemistry Part I for Class XII, the chapter The p-Block Elements. OpenStax, Chemistry 2e , Chapter 18.