Isothermal and adiabatic expansion compared

A gas at $2.2 \times 10^{5}\ \text{Pa}$ expands from $1.5\ \text{L}$ to $6.0\ \text{L}$, once at a steady temperature and once adiabatically ($\gamma = 1.40$). You will make the program draw both curves and find the work of each from the area under it.

The idea. Isothermal: $p = \dfrac{p_1V_1}{V}$. Adiabatic: $p = p_1\left(\dfrac{V_1}{V}\right)^\gamma$. The work is the area under each curve, which the function area adds up in thin strips.

Your tasks.

1. Work out the pressure along the isotherm, p_iso.
2. Work out the pressure along the adiabat, p_ad.
3. Find the work of each, W_iso and W_ad, with area.