Uses of Bernoulli's principle · Physics Class 11–12 | StemPy Lab
Course 9.2·Lesson 3 of 3
Uses of Bernoulli's principle
Bernoulli's principle explains many things. Water leaves a hole h below the surface at v=2gh
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Torricelli's law
A tank is open to the air, and a small hole is made h below the surface. At the surface and at the hole the pressure is the air's, and the water at the top hardly moves. Bernoulli's equation then gives
v=2gh
the speed of a stone dropped through h. The jet does not depend on the liquid's density.
Two drawings. On the left, a tank of liquid open to the air, with a small hole in the side at a depth h below the surface. A jet leaves the hole with the speed v equal to the square root of 2 g h. On the right, a Venturi meter: a horizontal pipe that narrows in the middle, with two vertical tubes, one over the wide part and one over the narrow part. The liquid in the tube over the narrow part is lower by the height delta h, because the pressure is lower where the speed is higher.
You should find that the jet goes farthest from a hole halfway down: a deep hole is fast but low, a high hole is slow.
The Venturi meter
A pipe narrows to a throat and widens again. The water speeds up in the throat, and its pressure drops. A manometer measures that drop, and Bernoulli's equation with continuity gives the speed, and so the flow rate.
Fast air, low pressure
A spray or a carburettor: fast air across the top of a tube lowers the pressure there, and the liquid below is pushed up into the stream.
A wing: its shape and tilt make the air above move faster, so the pressure below is higher, and the difference lifts the plane.
A spinning ball: one side drags the air along faster, and the ball swerves toward that side. This is the Magnus effect.
A roof in a storm: fast wind above, still air below, and the roof is pushed up.
Watch out. A fast stream has low pressure inside it. The slow air beside it does the pushing.
A worked example
A Venturi meter in a water pipe 12cm across has a throat 6.0cm across. The pressure in the throat is 15kPa lower. Find the flow rate.
Continuity. Half the diameter is a quarter of the area, so v2=4v1.
Bernoulli.15000Pa=21×1000kg/m3×(16−1)v12, so v12=2.0m2/s2 and v1=1.41m/s.
Flow rate.π(0.060m)2×1.41m/s=0.016m3/s, 16 litres each second.
Practise with new numbers
Try it in Python
The program finds the speed and the landing point of jets from several holes.
Remember these
Torricelli: v=2gh, whatever the liquid.
Venturi meter: the pressure drop in the throat gives the speed.
Fast air has low pressure: sprays, wings, swerving balls, roofs in storms.
Check yourself
Try each one on your own first. If you are stuck, open a hint. Then check with Show the answer.
How fast does water leave a hole 3.2m below the surface? (Take g=10m/s2.)
Would mercury come out of the same hole faster or slower than water?
Why does a strip of paper rise when you blow across its top?
A spinning cricket ball swerves. Toward which side?
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(Torricelli's law). A Venturi meter finds the speed of flow from the drop of pressure in a narrow throat. Sprays, the lift on a wing, a spinning ball's swerve and roofs lifted in storms all come from fast air having low pressure.
about 25 min1 simulation2 practice questions1 Python program4 questions to check yourself
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