Intrinsic and extrinsic semiconductors · Physics Class… | StemPy Lab
Course 27.1·Lesson 2 of 3
Intrinsic and extrinsic semiconductors
A pure semiconductor has as many holes as electrons. Adding a few atoms of a different group changes it. A donor atom (group 15) gives an extra electron and makes n-type material. An acceptor atom (group 13) makes a hole and gives p-type material. In either type, the product of the two carrier numbers stays ni2
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One foreign atom in a million
Take a crystal of silicon and replace one atom in every million by an atom of arsenic. The conductivity grows by a factor of tens of thousands. A few foreign atoms change the crystal more than heating it by a hundred degrees. This is doping, and every transistor depends on it.
The silicon crystal
Silicon is in group 14. Each atom has 4 valence electrons, and it shares one with each of 4 neighbours. These shared pairs are covalent bonds. At 0 K every electron sits in a bond. There are no free carriers, so pure silicon is an insulator. Germanium has the same structure.
n-type material
Replace a silicon atom by an atom of group 15, such as phosphorus, arsenic or antimony. It has 5 valence electrons. Four make bonds with the four neighbours. The fifth has no bond to join. It is held only weakly, and a small energy of about 0.05 eV or less sets it free.
The impurity atom is a donor, because it gives an electron.
On the energy diagram, the donor level lies just below the conduction band. At room temperature nearly every donor has given its electron to the conduction band.
The crystal stays neutral. The donor atom becomes a fixed positive ion, which cannot move.
The material is n-type. Electrons are the majority carriers and holes are the minority carriers.
p-type material
Replace a silicon atom by an atom of group 13, such as boron, aluminium, gallium or indium. It has only 3 valence electrons, so one bond lacks an electron. This is a hole. An electron from a neighbouring bond hops in easily, and the hole moves.
The impurity atom is an acceptor, because it takes an electron.
On the energy diagram, the acceptor level lies just above the valence band.
The atom becomes a fixed negative ion. The crystal stays neutral.
The material is p-type. Holes are the majority carriers and electrons are the minority carriers.
Two crystal pictures above and two energy diagrams below. On the left is a square lattice of silicon atoms, three by three, joined by double bond lines. The central atom is orange and marked P for phosphorus, a donor with five outer electrons. A red dot beside it, with an arrow and the words extra electron (free), is an electron that has no bond. On the right is the same lattice with a green central atom marked B for boron, an acceptor with three outer electrons, and an open blue circle on one of its bonds, labelled hole, the missing electron. Below the n-type lattice, an energy diagram shows a conduction band box above, a valence band box below, and an orange dashed donor level just below the conduction band with a red arrow going up to the band. Below the p-type lattice, the acceptor level is a green dashed line just above the valence band, with a blue arrow showing the hole entering the valence band.
How many carriers?
Doping adds carriers of one kind. It does not stop heat from making pairs, so recombination now has more of the majority carriers to meet. The result is the law of mass action:
nenh=ni2
The product stays at its intrinsic value. For an n-type crystal with donor number ND≫ni, nearly every donor gives an electron, so ne≈ND. The hole number is
nh=neni2≈NDni2
The full condition of neutrality is nh+ND=ne+NA, where NA is the number of acceptors. For silicon at 300 K, we use ni=1.0×1016m−3. NCERT prints 1.5×1016m−3, and older books use 1.45×1016m−3. The newer measurements are close to 1016m−3.
A worked example. Silicon has 5.0×1028 atoms in each cubic metre. One phosphorus atom is added for every 5.0×107 silicon atoms. Find the electron and hole numbers.
The donor number.ND=5.0×1075.0×1028m−3=1.0×1021m−3.
The electrons.ne≈ND=1.0×1021m−3.
The holes.nh=neni2=1.0×1021m−3(1.0×1016m−3)2=1.0×1011m−3.
The electrons outnumber the holes by 1010 to 1. Doping has made the crystal almost a one-carrier conductor. The crystal as a whole is still neutral.
Conductivity
Each kind of carrier adds to the conductivity. If the electron mobility is μe and the hole mobility is μh (drift speed per unit field), then
σ=e(neμe+nhμh)
For silicon, take μe=0.135m2/V s and μh=0.048m2/V s. Pure silicon has σ=1.6×10−19C×1016m−3×0.183m2/V s=2.9×10−4S/m.
Slide the donor power from 14 to 25. At which power does the electron curve start to rise away from the hole curve? Does the product ever change?
What temperature does
Heating a doped crystal adds more electron-hole pairs, but they matter little while ni≪ND. At a high enough temperature ni grows to the size of the doping, and the crystal turns intrinsic again. A device must work well below that temperature. For silicon this is a few hundred degrees above room temperature, and for germanium it is lower. This is one reason silicon replaced germanium.
Practise with new numbers
Try it in Python
The program makes a table. Each row has a dopant (none, a donor or an acceptor) at some ratio to the silicon atoms. It finds the electron and hole numbers and the conductivity.
Common mistakes
Saying an n-type crystal is negatively charged. It is neutral. The extra electrons are balanced by the positive donor ions.
Saying the majority carriers are fixed ions. Ions are fixed. Carriers are electrons and holes.
Forgetting that minority carriers exist. They are few, but they give the reverse current of a diode and they grow fast with temperature.
Using ne=ni in a doped crystal. Use ne≈ND, and then nh=ni2/ne.
Mixing up donor and acceptor. A donor is from group 15 and gives n-type. An acceptor is from group 13 and gives p-type.
Remember these
n-type: donors (P, As, Sb), ne≈ND, electrons are the majority carriers. p-type: acceptors (B, Al, Ga, In), nh≈NA, holes are the majority carriers.
The law of mass action: nenh=ni2.
Conductivity: σ=e(neμe+nhμh).
The crystal is neutral. Donor ions are positive and acceptor ions are negative, and none of them move.
References
NCERT Physics Class 12, Semiconductor Electronics, the sections on extrinsic semiconductors.
OpenStax University Physics Volume 3, the chapter Condensed Matter Physics, on semiconductors and doping.
Check yourself
Try each one on your own first. If you are stuck, open a hint. Then check with Show the answer.
Phosphorus is added to silicon. What kind of material results, and what are the majority carriers?
A p-type crystal has NA=2.0×1021m−3 and ni=1.0×1016m−3. How many electrons are there in each cubic metre?
Is an n-type crystal charged?
Why is a doped crystal a better conductor than a pure one even though doping adds very few atoms?
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