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Zinc reduces iron(III) ions: Zn(s) + 2Fe³⁺(aq) →… | StemPy Lab
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Zinc reduces iron(III) ions: Zn(s) + 2Fe³⁺(aq) → Zn²⁺(aq) + 2Fe²⁺(aq). Use E°(Zn²⁺/Zn) = -0.76 V and E°(Fe³⁺/Fe²⁺) = 0.77 V. What is Δ G° for this reaction?
Chemistry
Medium
High School (11–12)
Electrochemistry › Galvanic Cells, Electrode Potential and the Nernst Equation
Board Exam
AP
A-Level
IB
Created by
StemPy Lab
Zinc reduces iron(III) ions:
Zn
(
s
)
+
2
Fe
3
+
(
a
q
)
→
Zn
2
+
(
a
q
)
+
2
Fe
2
+
(
a
q
)
\text{Zn}(s) + 2\text{Fe}^{3+}(aq) \rightarrow \text{Zn}^{2+}(aq) + 2\text{Fe}^{2+}(aq)
Zn
(
s
)
+
2
Fe
3
+
(
a
q
)
→
Zn
2
+
(
a
q
)
+
2
Fe
2
+
(
a
q
)
. Use
E
∘
(
Zn
2
+
/
Zn
)
=
−
0.76
V
E^\circ(\text{Zn}^{2+}/\text{Zn}) = -0.76\ \text{V}
E
∘
(
Zn
2
+
/
Zn
)
=
−
0.76
V
and
E
∘
(
Fe
3
+
/
Fe
2
+
)
=
0.77
V
E^\circ(\text{Fe}^{3+}/\text{Fe}^{2+}) = 0.77\ \text{V}
E
∘
(
Fe
3
+
/
Fe
2
+
)
=
0.77
V
. What is
Δ
G
∘
\Delta G^\circ
Δ
G
∘
for this reaction?
−
590.6
kJ/mol
-590.6\ \text{kJ/mol}
−
590.6
kJ/mol
+
295.3
kJ/mol
+295.3\ \text{kJ/mol}
+
295.3
kJ/mol
−
295.3
kJ/mol
-295.3\ \text{kJ/mol}
−
295.3
kJ/mol
−
147.6
kJ/mol
-147.6\ \text{kJ/mol}
−
147.6
kJ/mol
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