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Which result is correct for the integral of 1/(√(16… | StemPy Lab
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Which result is correct for the integral of 1/(√(16 - x²)) on the interval -4 < x < 4?
Mathematics
Easy
High School (11–12)
Functions and Calculus › Integrals
A-Level
AP
IB
Created by
StemPy Lab
Which result is correct for the integral of
1
16
−
x
2
\dfrac{1}{\sqrt{16 - x^2}}
16
−
x
2
1
on the interval
−
4
<
x
<
4
-4 < x < 4
−
4
<
x
<
4
?
tan
−
1
x
4
+
C
\tan^{-1}\dfrac{x}{4} + C
tan
−
1
4
x
+
C
1
8
ln
∣
4
+
x
4
−
x
∣
+
C
\dfrac{1}{8}\ln\left|\dfrac{4 + x}{4 - x}\right| + C
8
1
ln
4
−
x
4
+
x
+
C
ln
∣
x
+
x
2
−
16
∣
+
C
\ln\left|x + \sqrt{x^2 - 16}\right| + C
ln
x
+
x
2
−
16
+
C
sin
−
1
x
4
+
C
\sin^{-1}\dfrac{x}{4} + C
sin
−
1
4
x
+
C
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