Fe2O3+2Al→2Fe+Al2O3\text{Fe}_2\text{O}_3 + 2\text{Al} \rightarrow 2\text{Fe} + \text{Al}_2\text{O}_3Fe2O3+2Al→2Fe+Al2O3. What mass of iron forms from 40 g40\ \text{g}40 g of iron(III) oxide? Use Fe=56\text{Fe} = 56Fe=56 and O=16\text{O} = 16O=16.
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