Tin(II) ions reduce iron(III) ions: Sn2++2Fe3+→Sn4++2Fe2+\text{Sn}^{2+} + 2\text{Fe}^{3+} \rightarrow \text{Sn}^{4+} + 2\text{Fe}^{2+}Sn2++2Fe3+→Sn4++2Fe2+. How many electrons does each tin(II) ion give away?
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