Three linked genes lie in the order P, Q, R. The map distance from P to Q is 10 cM and from Q to R is 20 cM. The interference between the two regions is 0.4. A heterozygote PQR/pqr is test crossed and 5000 progeny are counted. How many progeny are expected to be of the two parental types together?

BiologyAdvancedHigh School (11–12)Heredity and Evolution › Heredity and Inheritance Olympiad

Three linked genes lie in the order $P, Q, R$ . The map distance from $P$ to $Q$ is $10\ \text{cM}$ and from $Q$ to $R$ is $20\ \text{cM}$ . The interference between the two regions is $0.4$ . A heterozygote $\dfrac{PQR}{pqr}$ is test crossed and $5000$ progeny are counted. How many progeny are expected to be of the two parental types together?

← All Quizzes

← Two genes are linked on the same chromosome, 20 cM apart. A plant has the genotype Ab/aB (the dominant alleles are on different homologues). It is selfed, and there is no difference in the survival of gametes or zygotes. What fraction of the offspring is expected to show both recessive traits (aabb)?A dihybrid AaBb plant is test crossed to aabb, and independent assortment predicts four equal classes. Among 400 progeny the classes are 112, 98, 95 and 95. The critical value of chi-square at the 5% level is 7.81 for 3 degrees of freedom and 9.49 for 4. Which conclusion is correct? →

More onHeredity and Evolution › Heredity and Inheritance

Discussion (0)

Loading…

Discussion (0)

Problems on this topic