The sloping face of a wedge is smooth and makes $37^\circ$ with the floor ($\tan 37^\circ = 0.75$). A small block of mass $m$ is placed on this face. The wedge is then pushed so that it moves along the floor with a steady acceleration, as shown in the figure, and the block does not slide on it at all. Taking $g = 10\ \text{m/s}^2$, the acceleration of the wedge and the normal force on the block are

Fig. 1: A wedge on a horizontal floor with a smooth face at 37 degrees and a block of mass m resting on the face. A push on the vertical side of the wedge gives it an acceleration a, shown pointing left.