How much heat warms 2.5 kg2.5\ \text{kg}2.5 kg of water from 20 ∘C20\ ^\circ\text{C}20 ∘C to 80 ∘C80\ ^\circ\text{C}80 ∘C? (c=4186 J kg−1K−1c = 4186\ \text{J kg}^{-1}\text{K}^{-1}c=4186 J kg−1K−1.)
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