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The point (1, 1) lies on the curve 2x² + 3y² = 5. What… | StemPy Lab
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The point (1, 1) lies on the curve 2x² + 3y² = 5. What is dy/dx there?
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Functions and Calculus › Continuity and Differentiability
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StemPy Lab
The point
(
1
,
1
)
(1, 1)
(
1
,
1
)
lies on the curve
2
x
2
+
3
y
2
=
5
2x^2 + 3y^2 = 5
2
x
2
+
3
y
2
=
5
. What is
d
y
d
x
\dfrac{dy}{dx}
d
x
d
y
there?
2
3
\dfrac{2}{3}
3
2
0
0
0
−
3
2
-\dfrac{3}{2}
−
2
3
−
2
3
-\dfrac{2}{3}
−
3
2
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A curve is given by x = t³ and y = t². What is the slope dy/dx at t = 2? →
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