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The hydrocarbons ethyne, ethene, ethane and propane… | StemPy Lab
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The hydrocarbons ethyne, ethene, ethane and propane each lose a proton from carbon to give a carbanion. The carbanion that is easiest to form is
Chemistry
Hard
High School (11–12)
Organic Chemistry: Some Basic Principles and Techniques › Electronic Effects and Reaction Intermediates
JEE Main
A-Level
IB
Created by
StemPy Lab
The hydrocarbons ethyne, ethene, ethane and propane each lose a proton from carbon to give a carbanion. The carbanion that is easiest to form is
CH
2
=CH
−
\text{CH}_2\text{=CH}^{-}
CH
2
=CH
−
CH
3
CH
2
CH
2
−
\text{CH}_3\text{CH}_2\text{CH}_2^{-}
CH
3
CH
2
CH
2
−
HC
≡
C
−
\text{HC}\equiv\text{C}^{-}
HC
≡
C
−
CH
3
CH
2
−
\text{CH}_3\text{CH}_2^{-}
CH
3
CH
2
−
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Organic Chemistry: Some Basic Principles and Techniques › Electronic Effects and Reaction Intermediates
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