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The graph of y = ln(3x + 5) is drawn. What is its… | StemPy Lab
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The graph of y = ln(3x + 5) is drawn. What is its gradient at the point where x = 1?
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Functions and Calculus › Continuity and Differentiability
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StemPy Lab
The graph of
y
=
ln
(
3
x
+
5
)
y = \ln(3x + 5)
y
=
ln
(
3
x
+
5
)
is drawn. What is its gradient at the point where
x
=
1
x = 1
x
=
1
?
3
8
\dfrac{3}{8}
8
3
1
8
\dfrac{1}{8}
8
1
1
3
\dfrac{1}{3}
3
1
3
5
\dfrac{3}{5}
5
3
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