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The double angle 2 tan⁻¹1/5 has to be written… · Answer | StemPy Lab
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The double angle 2 tan⁻¹1/5 has to be written as one inverse sine. Which expression is correct?
Mathematics
Medium
High School (11–12)
Trigonometry › Inverse Trigonometric Functions
Board Exam
CUET UG
Created by
StemPy Lab
The double angle
2
tan
−
1
1
5
2\tan^{-1}\dfrac{1}{5}
2
tan
−
1
5
1
has to be written as one inverse sine. Which expression is correct?
sin
−
1
2
5
\sin^{-1}\dfrac{2}{5}
sin
−
1
5
2
sin
−
1
12
13
\sin^{-1}\dfrac{12}{13}
sin
−
1
13
12
sin
−
1
5
12
\sin^{-1}\dfrac{5}{12}
sin
−
1
12
5
sin
−
1
5
13
\sin^{-1}\dfrac{5}{13}
sin
−
1
13
5
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← In a right triangle the legs are 5 m and 12 m. The angle γ = tan⁻¹5/12 lies opposite the shorter leg. What is cosγ?
A table lists tan⁻¹1/x beside cot⁻¹x for several non-zero numbers x, with cot⁻¹ taking values in (0, π). In which rows do the two entries agree? →
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Trigonometry › Inverse Trigonometric Functions
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