Alpha particles of 7.7 MeV head straight at a gold nucleus, Z = 79. Using d = 2Z/KE × 1.44 MeV fm, how close do they come?

ChemistryMediumHigh School (11–12)Structure of the Atom › Isotopes and Isobars

Alpha particles of $7.7\ \text{MeV}$ head straight at a gold nucleus, $Z = 79$ . Using $d = \dfrac{2Z}{KE} \times 1.44\ \text{MeV fm}$ , how close do they come?

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