Pauling's relation gives $|\chi_\text{A} - \chi_\text{B}| = 0.102\sqrt{\Delta}$, where $\Delta$ (in $\text{kJ mol}^{-1}$) is the extra bond energy of $\text{A-B}$ over the geometric mean of the $\text{A-A}$ and $\text{B-B}$ bond energies. The bond dissociation energies are: $\text{A-A}$ $90\ \text{kJ mol}^{-1}$, $\text{B-B}$ $360\ \text{kJ mol}^{-1}$, $\text{A-B}$ $318\ \text{kJ mol}^{-1}$. In the AB molecule the B atom carries the partial negative charge, and $\chi_\text{B} = 3.2$. Find $10\chi_\text{A}$. The answer is an integer; round to the nearest whole number.