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Iron(II) ions catalyse the oxidation of iodide ions by… | StemPy Lab
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Iron(II) ions catalyse the oxidation of iodide ions by peroxodisulphate ions. The steps are: S₂O₈²⁻ + 2Fe²⁺ → 2SO₄²⁻ + 2Fe³⁺, then 2Fe³⁺ + 2I⁻ → 2Fe²⁺ + I₂. Which line names the catalyst and the intermediate?
Chemistry
Hard
High School (11–12)
Chemical Kinetics › Temperature, the Arrhenius Equation and Collision Theory
NEET
AP
A-Level
IB
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StemPy Lab
Iron(II) ions catalyse the oxidation of iodide ions by peroxodisulphate ions. The steps are:
S
2
O
8
2
−
+
2
Fe
2
+
→
2
SO
4
2
−
+
2
Fe
3
+
\text{S}_2\text{O}_8^{2-} + 2\text{Fe}^{2+} \rightarrow 2\text{SO}_4^{2-} + 2\text{Fe}^{3+}
S
2
O
8
2
−
+
2
Fe
2
+
→
2
SO
4
2
−
+
2
Fe
3
+
, then
2
Fe
3
+
+
2
I
−
→
2
Fe
2
+
+
I
2
2\text{Fe}^{3+} + 2\text{I}^- \rightarrow 2\text{Fe}^{2+} + \text{I}_2
2
Fe
3
+
+
2
I
−
→
2
Fe
2
+
+
I
2
. Which line names the catalyst and the intermediate?
Catalyst:
I
−
\text{I}^-
I
−
. Intermediate:
I
2
\text{I}_2
I
2
Catalyst:
Fe
2
+
\text{Fe}^{2+}
Fe
2
+
. Intermediate:
Fe
3
+
\text{Fe}^{3+}
Fe
3
+
Catalyst:
Fe
3
+
\text{Fe}^{3+}
Fe
3
+
. Intermediate:
Fe
2
+
\text{Fe}^{2+}
Fe
2
+
Catalyst:
SO
4
2
−
\text{SO}_4^{2-}
SO
4
2
−
. Intermediate:
Fe
2
+
\text{Fe}^{2+}
Fe
2
+
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Chemical Kinetics › Temperature, the Arrhenius Equation and Collision Theory
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