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In the proof that a quadrilateral with ∠ B + ∠ D = 180°… | StemPy Lab
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In the proof that a quadrilateral with ∠ B + ∠ D = 180° is cyclic, D is supposed to lie inside the circle through A, B, C. AD is extended to meet the circle at D'. Which fact leads to the contradiction?
Mathematics
Hard
High School (9–10)
General
Geometry › Circles
Olympiad
SAT
Created by
StemPy Lab
In the proof that a quadrilateral with
∠
B
+
∠
D
=
180
∘
\angle B + \angle D = 180^\circ
∠
B
+
∠
D
=
18
0
∘
is cyclic,
D
D
D
is supposed to lie inside the circle through
A
A
A
,
B
B
B
,
C
C
C
.
A
D
AD
A
D
is extended to meet the circle at
D
′
D'
D
′
. Which fact leads to the contradiction?
∠
A
D
C
\angle ADC
∠
A
D
C
is an exterior angle of the triangle
D
D
′
C
DD'C
D
D
′
C
, so it is greater than
∠
A
D
′
C
\angle AD'C
∠
A
D
′
C
, yet both equal
180
∘
−
∠
B
180^\circ - \angle B
18
0
∘
−
∠
B
∠
A
D
C
\angle ADC
∠
A
D
C
is a right angle
A
D
AD
A
D
and
B
C
BC
B
C
are parallel
∠
A
D
′
C
\angle AD'C
∠
A
D
′
C
is greater than
∠
A
D
C
\angle ADC
∠
A
D
C
, since
D
′
D'
D
′
is farther from
A
A
A
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