In the figure, a battery of emf $12\ \text{V}$ and internal resistance $1.0\ \Omega$ is joined to three resistors and a capacitor. The capacitor was uncharged at first, and the battery has been connected for a very long time. The connecting wires have no resistance, and the capacitor has a capacitance of $2.0\ \mu\text{F}$. What is the charge now stored on the capacitor?

Fig. 1: A circuit with a 12 V battery of internal resistance 1.0 ohm drawn on the left. A 5.0 ohm resistor is in the top wire and a 6.0 ohm resistor stands on the right between the top and bottom wires. A second branch across the 6.0 ohm resistor holds a 4.0 ohm resistor in series with a capacitor of 2.0 microfarad. The capacitor is uncharged at the moment the battery is first joined.