Hot phosphine decomposes: 4PH3(g)→P4(g)+6H2(g)4\text{PH}_3(g) \rightarrow \text{P}_4(g) + 6\text{H}_2(g)4PH3(g)→P4(g)+6H2(g). At one instant the phosphine concentration is falling by 0.064 mol L−10.064\ \text{mol L}^{-1}0.064 mol L−1 each second. How quickly is hydrogen being made at that instant?
Log in to join the discussion.
Loading…